Tuesday, 30 March 2021
The Size of the Human Heat is almost same size of their Hand Fist || FACTS by SCIENTECHPLUS
Sunday, 28 March 2021
Fruits is one of best source of healthy diet for healthy body and mind || by scientechplus
In the modern time era, lot's of people prefer to eat fast food. By as the time move forward, people makes their live full fast.
So in the less time people most of all prefer to eat tasty and oil product food. which is know by the name 'Fast Food'.
It is right to eat sometime, but only for some period of time. But it is not like that, people make this fast food as their nutritional source for health.
Because of that, many crowd you see in the hospital and clinic side of patient.
Did you have any idea about, how this happen ?. It is happen because of our wrong pattern of eating food in out daily routine.
We totally forgotten about our health in the daily load work. But as we all aware about the great thought "Health is Weath".
For all of us heath is our first priority, isn't it? It is totally our responsibility to maintain our health, well and well.
How to maintain health "Well n Well"
By applying proper diet plan in our daily food routine.
Along with good food some fruits also add in your meal for getting best nutritional result.
So in this season add grapes fruit in your daily nutrition to make fruitful day.
Papaya : Add some papaya fruit in your meal to make pleasant bodily and mentally. Papaya is very good for eyes, hair, immunity problem.
The taste of papaya is such lovely sweet taste. It is very soft to eat. This papaya is eaten by even diabetes patient also.
It is much more safe for all types of disease patient and also healthy people.
Good bye!!!
Thank you...!!!
If sinθ = 7/25, find the values of cosθ and tanθ || Trigonometry sum || by SCIENTECHPLUS
Friday, 26 March 2021
List the application of microwaves and radio waves
Application of the microwaves
List the various waves of the electromagnetic spectrum
List the various waves of the electromagnetic spectrum !!!
Ans : There are seven types of electromagnetic spectrum.
The seven electromagnetic spectrum is,
• Radio waves
• Microwaves
• Infrared waves
• Visible light rays
• Ultraviolet rays
• X-rays
• Gamma rays
So these are the seven electromagnetic spectrum.
The Applied Electronics MCQ || Test Revision paper
The Applied Electronics MCQ || Test Revision paper !!!
1) The types of coupling used in the BJT (Bipolar Junction Transistor) amplifier.
a) Resistance capacitance (RC) coupling.
b) Impedance coupling
c) Transformer coupling
d) All of the above
Answer : (d) All of the above.
2) The phase shift of positive feedback circuit.
a) 90° Degree
b) 180° Degree
c) 45° Degree
d) 0° or 360° Degree
Answer : (d) 0° or 360° Degree.
3) The current gain (β) in the power amplifier.
a) Low 5 to 20
b) Low 40 to 65
c) Low 70 to 95
d) Low 25 to 40
Answer : Low 5 to 20
4) What is the angle of conduction of Class A power amplifier ?
a) 90° Degree angle
b) 180° Degree angle
c) 45° Degree angle
d) 360° Degree angle
Answer : 360° Degree angle
5) What is the angle of conduction of Class B power amplifier ?
a) 90° Degree angle
b) 180° Degree angle
c) 45° Degree angle
d) 360° Degree angle
Answer : 180° Degree angle
6) What is the angle of conduction of Class C power amplifier ?
a) 90° Degree angle
b) 100° to 150° Degree angle
c) 180° to 200° Degree angle
d) 360° Degree angle
Answer : 100° to 150° Degree angle
7) What is the angle of conduction of Class AB power amplifier ?
a) 90° Degree angle
b) 100° to 150° Degree angle
c) 180° to 200° Degree angle
d) 360° Degree angle
Answer : 180° to 200° Degree angle
8) What is the application of single tuned amplifier in the below option.
a) T.V Receiver
b) Radio Receiver
c) Tuned Radio Frequency (TRF) Receiver
d) Both a) T.V Receiver & c)
Answer : d) Both a) T.V Receiver & c) Tuned Radio Frequency (TRF) Receiver
9) What are the application of RC coupled amplifier.
a) In Tape Recorder
b) In stereo amplifier
c) Widely used as voltage amplifier
d) All of the above
Answer : d) All of the above
10) The different types of power amplifier.
a) Class A power amplifier
b) Class B power amplifier
c)Class C power amplifier
d) All of the above
Answer : d) All of the above
Wednesday, 24 March 2021
The heathy benefits of papaya for healthy body immunity and mental problem
Here are the chart table containing by papaya fruit :
Monday, 22 March 2021
Today's 2021 year play Holi festival with corona virus with some taking precaution !!!
Tuesday, 9 March 2021
Explain the refraction of light on the basis of wave theory and also prove the laws of refraction of light.
i) The incident rays, refracted rays and normal lie in the equivalent plane.
ii) The incident ray and refracted ray lie on opposite sides of normal.
iii) The ratio of velocity of light in rarer medium to velocity of light in denser medium is a constant called refractive index of denser medium with respect to rarer medium.
Explanation laws of refraction :
i) Let consider XY be the plane refracting surface separating two media air and glass of refractive indices μ1 and μ2 serially.
ii) A plane wavefront AB is developing at an angle towards XY from the air medium. It is bounded by the rays AA1 and BB1 which are incident rays.
iii) When point 'A' reaches 'A1' then point 'B' will be at 'P'. It even now has to cover distance PB1 to reach XY.
iv) According to Huygens' principle the secondary waves will originate from A1 and will spread over a hemisphere in the glass.
v) All the rays between AA1 and BB1 will reach XY and spread over the hemispheres of increasing radii in the glass. The surface of tangential of all such hemispheres is RB1. This allow to rise refracted wavefront B1R in the glass.
vi) A1R and B1R1, are refracted rays.
vii) Let consider c1 and c2 be the velocities of light in air and glass .
viii) At any instant of time 't' distance covered by the incident wavefront from point P to B1 = PB1 = c1t.
The distance covered by the secondary wave from point A1 to R = A1R = c2t.
Proof of laws of refraction:
angle AA1M + angle MA1P = 90° .................................(1)
and angle MA1P+ angle PA1B1 = 90° ...........................(2)
From equations (1) and (2),
angle AA1M = angle PA1B1 = i
ii) Similarly, angle NA1R = angle N1B1R1 = r
We have, angle N1B1R1 + angle N1B1R = 90°.............(3)
and angle N1B1R + angle A1B1R = 90° ......................(4)
From equations (3) and (4)
angle N1B1R1 = angle A1B1R = r
iii) In triangle A 1PB1, sin i = PB1/A1B1 = c1t/A1B1................(5)
iv) In triangle A1RB1, sin r = A1R/A1B1 = c2t /A1B1..............(6)
v) Dividing equation (5) by (6),
Therefore sin i/ sin r = c1/ c2....................(7)
Also c1/ c2 = μ2/ μ1 = 1μ2 ......................(8)
Where as 1μ2 = R.I. of water with respect to air,
sin i/ sin r = μ2/ μ1
vi) From the explanation, it is clear that incident rays AA, BB, refracted rays A,R, B,R and normal MN and MIN lie on the same plane XY. Also incident ray AA, and refracted ray AR lie on opposite sides of normal MN. Therefore, laws of refraction can be explained.
THE END
Thank you
Sunday, 7 March 2021
With the help of a neat diagram | explain the reflection of light from the plane reflecting surface on the basis of wave theory of light.
So here first of all we know that,
What is the laws of reflection :
i) In the laws of reflection, the incident rays, reflected rays, and normal to the reflecting surface at the point of incidence, all lie in the same level.
ii) In the laws of reflection, the incident rays and the reflected rays lie on the opposite sides of the normal.
iii) The angle of incidence is equal or we can say equivalent to the angle of reflection.
For clear understanding the law of reflection in simple and easy way. So for that lets see the simple explanation about all these points.
Explanation :
i) The plane wavefront AB is developing at an angle towards plane reflecting surface XY.AA1 and BB1 are incident rays.
ii) When point 'A' come to XY at A1, than ray at 'B' reaches at point P and it has to cover distance PB1 to reach the reflecting surface XY.
iii) Let's consider 't' be the time to required to cover distance PB1.
In this time meantime, the secondary waves are emitted from the point A1 and it will spread over the hemisphere of the radius A1R in the same medium.
The distance covered by the secondary waves to reach from A1 to R in time 't' is same as the distance covered by the primary waves to reach from point P to B1.
So therefore A1R = PB1 = ct.
iv) All other rays in between AA1 and BB1 will reach XY after A1 and before B1. Therefore they will also emits secondary waves of the decreasing radii.
v) The surface touch all such hemispheres is RB1 which is reflected wavefront, bounded by the reflected rays A1R and B1Q.
vi) Let's draw A1M perpendicular to XY and B1N perpendicular to XY.
Thus, the angle of incidence is angle AA1M = angle BB1N = i and the angle of reflection is angle MA1R = angle NB1Q = r.
angle RA1B1 = 90 - r
angle PB1A1 = 90 - i
vii) In the triangle A1RB1 and triangle A1PB1
Here angle A1RB1 congruent to angle A1PB1
A1R = PB1,............ (Reflected waves travel in equal in same medium in equal time).
A1B1 = A1B1.........(Common side)
Therefore triangle A1RB1 congruent to triangle A1PB1
Therefore angle RA1B1 = angle PB1A1
Therefore 90 - r = 90 - i
Therefore i = r
viii) From the above given figure, it clear that the incident ray, reflected ray and normal lie in the same level or plane.
ix) This laws of reflection of light from the plane reflecting surface on the basis of Huygen's wave theory.
THE END
Thank you
Saturday, 6 March 2021
The Huygen's construction of spherical wavefront in simple and easy way !!!
Explain the Huygen's construction of plane wavefront in easy and simple way !!!
Explain the Huygen's construction of plane wavefront in easy and simple way !!!
So let's come to know,
i) The plane wavefront is formed when the point of observation is very far away or we can say at infinity from the primary source of light.
ii) So here let's PQR represent a plane wavefront at any instant.
So according to the Huygen's principle, all the points on this wavefront will act as a secondary source of light and sending out secondary wavelets in the forward direction only.
iii) For make it to undestand easily, first of all we need to draw hemisphere with Point P,Q,R.... as centres and 'ct' as a radius.
The surface tangential to all such hemisphere is P1Q1R1....at instant 't'.
The new wavefront at time 't'.
iv) The plane wavefront is propagated or travel as a plane waves in the homogeneous isotropic medium. Therefore they are parallel to each other.
v) PP1N1, QQ1N2, RR1N3 these are the wave normal at point P,Q,R respectively.
These wave normal shows the direction of propagation of the plane wavefront.
vi) The new wavefront P1Q1R1 is parallel to the primary wavefront PQR.
THE END
Thank you....!!!!
Difference in between primary source of light and secondary source of light in easy way !!!
Primary source of light
i) The primary source of light is a real source of light.
ii) Primary source of light sends out primary waves in the all possible directions.
iii) The primary source of light is effective at every point on it's surface.
iv) The primary source of light is situated in the air.
The secondary source of light
i) The secondary source of light is a fictitious source of light.
ii) The secondary source of light sends out secondary waves only in the forward direction.
iii) The secondary waves is effective only at the points where it touches the envelope.
iv) The secondary source of light is situated on the wavefront.
THE END
Friday, 5 March 2021
State what are the Huygen's principle statement !!!
State and explain the main characteristics of the wavefront in easy and simply way.
What is the expecting wavefront shape when the portion of the wavefront of light from a distant star intercepted by the earth ?
Thursday, 4 March 2021
What is the expecting shape of the wavefront when light emerging out of a convex lens ?
Hello dear all readers,
What is the expecting shape of the wavefront when light diverging from a point source ?
Wednesday, 3 March 2021
What are the main characteristics of the wave normal !!!
Hello dear all readers,
Welcome to this concept, so here in this concept you come to know about the main characteristics of the wave normal in easy and simple way.
So let's come to our topic,
i) The wave normal gives the direction of propagation of wave.
Let's take an one example, the medium through which wave is propagated, for an example 'air' so the wave is move in the direction of air simply.
Actually medium or we can say channel gives the direction for propagation of wave.
So it means that, the wave normal work according to the medium through which is allow to propagate.
ii) The wave normal is perpendicular to the wavefront.
Explanation : As you can see in the given image, the wave normal is perpendicular to the wavefront.
It means that, the wave normal make an angle with wavefront is 90° Degree.
iii) In a homogeneous isotropic medium, the wave normal is same as direction of ray of light.
Explanation : In a homogeneous isotropic medium or channel, the wave normal is same as direction of light.
It means that , First of all we have to know that, what is homogeneous ?
Homogeneous : Homogeneous is a uniform structure.
Isotropic material : The isotropic material whose properties remains same when tested in different different directions.
When we allow to propagate wave normal in the Homogeneous isotropic medium then the direction of the wave normal is in the direction of ray of light.
iv) Wave normal is drawn from the point of generation of wavefront.
Explanation : Actually the wave normal is start from the point where wavefront is generated.
So we hope you understand this concept very simply and easily.
If you have any doubt related to this concept than feel free to ask us.
We feel good to reply you as soon as possible.
Goodbye !!!
Thank you...!!!
Tuesday, 2 March 2021
State the different types of wavefront with suitable examples !!!
Hello dear all readers,
Welcome to this concept, so in this concept you come to know the different types of wavefronts with examples.
So let's explore this concept !!!
The wavefront is three types,
i) Spherical wavefront
ii) Plane wavefront
iii) Cylindrical wavefront
So let's know about this different wavefronts with an examples !!!
i) Spherical wavefront : The wavefront which is originating from a point source of light at some finite distance is called as or known as 'spherical wavefronts'
The example of this spherical wavefronts is : The candle flame, which we use in our day to day life in the moments such as birthday, marriage anniversary, or when electricity cut off.
The candle flame glow in the form of spherical wavefront.
ii) Plane wavefront : The wavefronts which is originating from a point source of light at infinite distance is called as or known as 'plane wavefront'.
The example of this plane wavefront is : The light from the sun arrives at the surface of the earth in the form of plane wavefront.
iii) Cylindrical wavefront : The wavefront which is originating from the linear source or slit of light at some finite distance is called as or known as 'cylindrical wavefront'.
The example of this cylindrical wavefront is : When a tube light is glow, it glow in the form of 'cylindrical wavefront'.
So we hope you understand this concept in simply and nicely.
So if you have any query related to this concept than feel free to ask us.
If in your mind have any idea to know something in simple and easy way than write in the comment box.
Good bye !!!
Thank you...!!!
Monday, 1 March 2021
National science day celebrated in the remembrance of physicist C.V Raman !!!
History of The National Science Day
What are the aim of celebrating National Science Day ?
The theme of National Science Day 2021
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