Solution:-
t = 20 second.
u = 72 km/hr = 72×1000 / 3600
u = 20 m/s
v = 36 km/hr = 36×1000 / 3600
v = 10m/s
a = v - u / t
= 10 - 20 / 20
= -10 / 20
a = - 0. 5 m/s2
v2 = u2 + 2as
S = v2 - u2 / 2a
= (10)2 - (20)2 / (2 ) × (- 0.5)
= 100 - 400 / -1
= -300 / -1
S = 300 m
∴ The length of the tunnel is 300m.
Hello friends my name is Rajakumar Dayashankar Gupta . Here I am started to write blog on name scientechplus . I am started to writing this blog post on science , technology and engineering since 2020 . I completing my ssc , than after I go for stream in science field , than after completing my 12th science than later I realize my self , I am interested in electronics fields , so I start learning in diploma electronics engineering . My journey is quite interesting to choosing right decision of my aim . And I want to explain the concept in simple and precise way . I every time want to learn something new , it means that something new from open minded from our environment . To learn something new from our expectation . It quite special and very interested to hear that , when we imagine or think we go to learn something very uniqueness our eyes fill with glow , that moment is such a very great pleasurable moment we feel isn't it ? . And I want to share the information , facts , knowledge related to all science , technology and engineering in detail , simple and precise way .
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